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A 2.05 M Aqueous Solution

 Multiple Choice QuestionsMultiple Choice Questions

21.

18 grand of glucose (C6H12O6) is added to 178.two 1000 of water. The vapour pressure of water for this aqueous solution at 100o C is

  • 759.00 Torr

  • 7.threescore Torr

  • 76.00 Torr

  • 76.00 Torr


C.

76.00 Torr

fraction numerator straight P to the power of straight o minus straight P subscript straight s over denominator straight P subscript straight s end fraction space equals space straight n over straight N  fraction numerator 760 minus straight P subscript straight s over denominator straight P subscript straight s end fraction space equals space fraction numerator begin display style 18 over 180 end style over denominator begin display style fraction numerator 178.2 over denominator 18 end fraction end style end fraction space equals space fraction numerator begin display style 1 over 10 end style over denominator 9.9 end fraction space equals space fraction numerator 0.1 over denominator 9.9 end fraction  760 space minus space straight P subscript straight s space equals space 1 over 99 straight P subscript straight s  760 space straight x space 99 space minus space straight P subscript straight s space straight x space 99 space equals space straight P subscript straight s  760 space straight x space 99 space equals space 100 space straight P subscript straight s  space straight P subscript straight s space equals space fraction numerator begin display style 760 space straight x space 99 end style over denominator 100 end fraction space equals space 752.4


22.

A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60 g mol–1) in the same solvent. If the densities of both the solutions are assumed to be equal to i.0 gcm–3, molar mass of the substance will be –

  • xc.0g mol–one

  • 115.0g mol–1

  • 105.0g mol–1

  • 105.0g mol–one


D.

105.0g mol–1

Solutions with the same osmotic pressure are isotonic
Let the molar mass of the substance be M

πone =ConeRT=C2RT =πtwo
So, C1 = C2
As density of the solutions are same
So comma space fraction numerator 5.25 over denominator straight M end fraction space equals space 15 over 60  straight M space equals space fraction numerator 5.25 space straight x space 60 over denominator 1.5 end fraction space equals space 210


23.

The density (in yard mL–1) of a 3.60 G sulphuric acrid solution that is 29% HiiSo4 (Tooth mass = 98 m mol-) past mass volition be

  • 1.64

  • 1.88

  • 1.22

  • 1.22


C.

1.22

Let the density of solution be 'd'
Molarity of solution given = 3.6
i.e. one litre of solution contains iii.half-dozen moles of HiiAnd thenfour
or 1 litre of solution contains 3.6 × 98 gms of HtwoSO4
Since, the solution is 29% by mass.
100 gm solution contains 29 gm HiiSOfour
100/d ml l  solution contains 29 gm of H2SO4.
1000 ml solution contains 3.6 × 98 gm of HiiSo4
3.6 space straight x space 98 space equals space fraction numerator 29 space straight x space straight d over denominator 100 end fraction space straight x space 1000
d = 1.22


24.

The solubility product of a common salt having general formula MXtwo, in water is 4 10 10-12. The concentration of M2+ ions in the aqueous solution of the salt is

  • ii.0 x x-6 M

  • one.0 10 10-4 M

  • i.vi x 10-4 M

  • i.six ten 10-iv Thou


B.

1.0 x 10-iv Yard

MX subscript 2 space rightwards harpoon over leftwards harpoon with space space space space space space space space space space space space space on top stack straight M to the power of 2 plus end exponent with straight S below space space plus stack space 2 straight X to the power of minus with straight S below  straight K subscript sp space equals space 4 straight s cubed comma space straight S thin space equals space 3 square root of straight K subscript sp over 4 end root space equals space 1 space straight x space 10 to the power of negative 4 end exponent


25.

At eightyo C, the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of 'A' and 'B' boils at fourscoreo C and 1 atm pressure, the amount of 'A' in the mixture is (i atm = 760 mm Hg)

  • 52 mol percent

  • 34 mol percent

  • 48 mol pct

  • 48 mol percent


D.

48 mol percent

PT = PoTenA + Po10B
760 = 520XA+ PoB(1-10A)
⇒ = 0.5
Thus, mole% of A = l%


26.

The volume of a colloidal particle, 5C as compared to the volume of a solute particle in a true solution FiveS, could be


C.

straight V subscript straight C over straight V subscript straight s asymptotically equal to space 10 cubed


27.

Density of a ii.05 One thousand solution of acetic acid in h2o is 1.02 chiliad/mL. The molality of the solution is

  • 1.14 mol kg–i

  • 3.28 mol kg–1

  • 2.28 mol kg–1

  • 2.28 mol kg–1


28.

Equal masses of methane and oxygen are mixed in an empty container at 25ºC. The fraction of the total pressure level exerted by oxygen is

  • 2/3

  • (1/three) 10 (273 / 298)

  • one/iii

  • 1/three


C.

one/three

Permit the mass of methyl hydride and oxygen is w

mole fraction of oxygen

space equals space fraction numerator begin display style straight w over 32 end style over denominator begin display style straight w over 32 end style plus begin display style straight w over 16 end style end fraction  space equals space fraction numerator begin display style 1 over 32 end style over denominator begin display style 1 over 32 end style plus begin display style 1 over 16 end style end fraction space equals space fraction numerator begin display style 1 over 32 end style over denominator begin display style 3 over 32 end style end fraction space equals space 1 third

Let the total force per unit area be P The pressure exerted by oxygen (fractional force per unit area) = 10O2 ×  Ptotal
 P =1/iii


29.

The vapour pressure of h2o at twentyoC is 17.5 mm Hg. If 18 g of glucose (C6H12Ohalf-dozen) is added to 178.two g of water at xxoC, the vapour pressure level of the resulting solution will be

  • 17.675 mm Hg

  • 15.750 mm Hg

  • 16.500 mm Hg

  • 16.500 mm Hg


D.

16.500 mm Hg

fraction numerator straight P to the power of 0 minus straight P subscript straight s over denominator straight P subscript straight s end fraction space equals space straight X space subscript solute  fraction numerator 17.5 space minus space straight P subscript straight s over denominator straight P subscript straight s end fraction space equals space fraction numerator 0.1 over denominator 10 end fraction  fraction numerator 17.5 space minus space straight P subscript straight s over denominator straight P subscript straight s end fraction space equals space 0.01  space rightwards double arrow space straight P subscript straight s space equals space 17.325 space mm space Hg


30.

A mixture of ethyl alcohol and propyl booze has a vapour force per unit area of 290 mm at 300 K. The vapour pressure level of propyl booze is 200 mm. If the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be

  • 350

  • 300

  • 360

  • 360


A.

350

Let the vapour pressure of pure ethyl alcohol be P,
According to Raoult'due south police force 290 = 200 × 0.4 + P × 0.vi
P = 290-lxxx/0.half dozen = 350 mm Hg


  • ii
  • 3
  • iv

A 2.05 M Aqueous Solution,

Source: https://www.zigya.com/competition/jee/study/Chemistry/CH/Solutions/CHENJE12157298/20

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